how many terms of arithmetic sequence 99,97,98... must be added to get 900?
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here a=99,d=-2and l=900
so a+(n-1)d=900
99+(n-1)×-2=900
-2×(n-1)=900-99=801
n-1=801÷-2
it is not possible because n must be +ve.
so a+(n-1)d=900
99+(n-1)×-2=900
-2×(n-1)=900-99=801
n-1=801÷-2
it is not possible because n must be +ve.
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