How many terms of G.P. 3, 32, 33, … are needed to give the sum 120?
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Explanation:
let A1=3
a²=32
r=?
for finding r :
r=A1/A2
r=3/32
r=0.093
G.P= 3,32,33......
Sn=120
let's substitute in the formula:
a(r power n - 1)/ r-1
3(0.093 power 120 -1)/0.093-1
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