how many terms of the A.P.1 8,16,14....,be taken so that their sum is zero
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4
Answer:
As per question,
Sn = 0
n/2(2a + (n - 1)d) = 0
Here, first term is 18 and common difference = (-2)
So we have...
n/2(18×2 + (n - 1)(-2)) = 0
n - 1 = 18
n = 19
So, we should take 19 terms of the AP
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