Question

one of the factor of is
(x-1)-(x²-1). ans is x-1
please give me a solution of this very fast after 4hour my exam is there

Answer 1

Step-by-step explanation:

let us assume p(x) = (x-1) - (x² - 1)

=> p(x) =  (x-1) - (x-1)(x+1)      (using a² - b² = (a + b)(a - b)

=> p(x) = (x - 1)(1 - (x + 1))

=> p(x) = (x-1)(-x)

therefore, factors of p(x) are (x - 1) and (-x)

Answer 2

Answer:

$\boxed{ - x(x-1)} \: is \: the \: factor$

Step-by-step explanation:

$(x - 1) - ( {x}^{2} - 1)$

$\Longrightarrow (x - 1) - (x + 1)(x - 1)$

$\Longrightarrow (x - 1)[1 - (x + 1)]$

$\Longrightarrow \boxed{ - x(x-1)}$

Formula used:

$( {a}^{2} - {b}^{2} ) = (a + b)(a - b)$

$( {x}^{2} - 1)$

$= ( {x}^{2} - {1}^{2} )$

$= \boxed{(x + 1)(x - 1)}$