How many terms of the A.P. 20, 19/3, 18/2, ... be taken so that their sum is 300?
Answers
Answered by
1
Answer:
25 and 36, sum of all terms from 26th to 36th is zero.
Answered by
7
Answer:
36 or 25
Step-by-step explanation:
a = 20, d = -2/3
Sn = n/2 [2a + (n-1)d]
300 = n/2 [2×20 + (n-1) ( -2/3)
300 = n/2 [ 40 -2/3n + 2/3]
300 = n/2 [ 122-2n/3]
300 = n(122 - 2n)/ 2×3
300 = 122n - 2n^2/6
300×6 = 122n - 2n^2
1800 = 122n - 2n^2
2n^2 - 122n + 1800 = 0
splitting middle term
2n^2 - 50n -72n +1800 =0
2n( n - 25) - 72 ( n-25) =0
(2n - 72) ( n - 25) =0
2n-72=0 or n-25=0
n= 72/2 or n = 25
n= 36 or n = 25
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