Math, asked by Rowdyboe, 11 months ago

. How many terms of the A.P. 20, 191/3,182/3
.. be taken so that their sum is 300?

Answers

Answered by Aniruddhk

3

D= -2/3

Sn= n/2 [2a+(n-1)d]

300= n/2[40+(n-1)(-2/3)]

600=n[40-2/3n+2/3

600=n[122/3-2n/3]

600=n[122-2n]/3

1800=122n-2n^

N^2-61n+900=0

By middle term splitting we can find the answer

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