How many terms of the A. P.: 27, 23, 19, 15, ... have a sum 95?
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a =27
d=23-27=-4
An=95
An=a+(n-1)d
95=27+(n-1)-4
95-27=-4n+4
68=-4n+4
68-4=-4n
64=-4n
64/4=n
16=n
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reemaanver999:
Ur answer is Wrong..!
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Hope this helps....... Do mark my answer as brainliest....!
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@Reema
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