Math, asked by paporirai2241, 23 days ago

How many terms of the arithmetic progression 12, 18, 24 must be taken so that their sum is 210?

Answers

Answered by Anonymous
8

Given :-

  • ➊ First term = 12
  • ➋ Common Difference = 18 - 12 = 6
  • ➌ Sum of terms = 210

To Find :-

  • ➊ Number of terms must be taken so that their sum is 210

Solution :-

By using Sn Formula

 \large \longmapsto \underline{ \boxed{ \bf  \red{S_n =  \frac{1}{2} \bigg[2a + (n - 1)d \bigg]}}} \\

Here :-

  • Sn = Sum of all terms
  • a = First term
  • n = number of terms
  • d = common difference

Substitute values in formula

:\implies \tt210 =  \frac{1}{2} \bigg[2 \times 12 + (n - 1)6 \bigg] \\

:\implies \tt210 \times 2 =  \bigg[24+ (n - 1)6 \bigg] \\

:\implies \tt420 =  \bigg[24+ (n - 1)6 \bigg] \\

:\implies \tt420 - 24 =(n - 1)6  \\

:\implies \tt396 =(n - 1)6  \\

:\implies \tt \frac{396}{6}  =n - 1  \\

:\implies \tt66  =n - 1  \\

:\implies \tt n = 66 + 1  \\

:\implies \boxed{ \tt n =67}\\

Answered by sairishipopuri2010
1

Answer:

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