How many terms of the sequence -12,-9,-6,-3,.......must be taken to make the sum 54?
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Question :
How many terms of the sequence -12,-9,-6,-3,.......must be taken to make the sum 54?
Answer :
As per the data given ,
First term = a = - 12
Common difference = d = -9 - (-12) = 3
Sum = s = 54
Number of terms = n = ??
In an Arithmetic sequence ,
Sum (s) = [n/2 (2a + (n-1) d )]
substitute the values known to find the unknown value " n " .
54 = [n/2 (2 × -12 + (n-1) -3 )]
Solve this equation for the value of " n "
Value of n = 13..
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