Question

How many three digit numbers are divisible by 6 which always leaves remainder 1?

Answer 1

the 3 digit numbers when divided by 6 leqves remainder 1 are
103, 109.......997
where a=103, d= 109-103=6 and An= 997
An= a+(n-1)d
997=103+(n-1)×6
(n-1)6=997-103=894
n-1=894/6=149
n=149+1=150
so, there are 150 numbers

Answer 2

Answer:

150

Step-by-step explanation:

there are 900 3digit no.s

so;no.s divisible by6are

900/6=150