Math, asked by muhasinkoolan, 3 months ago

How many three-digit numbers are there, which leave a remainder 2 on division by 8?

Answers

Answered by anajuliabalbino15

2

Step-by-step explanation:

A.P = 101,110,119,..,992

An= a+(n-1)d

a=101

d=9

An=992

992 = 101 +(n-1)9

992-101 = (n-1)9

891 = (n-1)9

(n-1) = 99

HOPE THIS HELPS ( ;

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