Math, asked by ansarisuhel0328, 7 hours ago

How many three-digit numbers can be formed such that ones place is only occupied by 5, 6, 7 or 9?

answer :5

Answers

Answered by rakshitrohatgi

1

Answer:

360

Step-by-step explanation:

in every 10 number in the 100's there are 4 numbers which end with 5,6,7,9.

So, every 100 numbers there are 40 digits starting fro hundred there are total 900 triple digit numbers. so 9*40=360

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