How many three-digit numbers can be formed such that ones place is only occupied by 5, 6, 7 or 9?
answer :5
Answers
Answered by
1
Answer:
360
Step-by-step explanation:
in every 10 number in the 100's there are 4 numbers which end with 5,6,7,9.
So, every 100 numbers there are 40 digits starting fro hundred there are total 900 triple digit numbers. so 9*40=360
Similar questions
Math,
4 hours ago
History,
4 hours ago
Computer Science,
4 hours ago
Chemistry,
7 hours ago
Computer Science,
7 months ago
Science,
7 months ago