Math, asked by wenkat6542, 9 months ago

how many three digit numbers which are neither divisible by 4 nor
5 is​

Answers

Answered by amitnrw
7

540  three digit numbers are neither divisible by 4 nor  5

Step-by-step explanation:

Number divisible by 4

from 100 to 999

are 100 , 104 ,............................ 996

= 225 numbers

Number divisible by 5

from 100 to 999

are 100 , 105 ,............................ 995

= 180 numbers

but these both contains number divisible by 20

Number divisible by 20

from 100 to 999

are 100 , 105 ,............................ 980

= 45 numbers

Number Divisible by either 4 or 5

= 225 + 180 - 45

= 360

Number neither divisible by  4 or 5

= 900 - 360

= 540

540  three digit numbers are neither divisible by 4 nor  5

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Answered by lublana
1

The three digits numbers which are neither divisible by 4 nor 5=540

Step-by-step explanation:

Three digit numbers are

100,101,102,.....,999

Three digits number divisible by 4

100,104, ....996

a=100

d=104-100=4

When the difference between two consecutive terms is constant then the sequence is  in A.P

Given terms in A.P

a_n=a+(n-1)d

Substitute the values

996=100+(n-1)4

996-100=4(n-1)

\frac{896}{4}=n-1

224=n-1

n=224+1=225

The three digit number divisible by 4=225

Three digits number is divisible by 5

100,105,....995

d=105-100=5

The difference between two consecutive term is constant

Therefore, it forms an A.P

995=100+(n-1)5

995-100=5(n-1)

\frac{895}{5}=n-1

179=n-1

n=179+1=180

The three digits number is divisible by 4 and 5 are

100,120,140,....980

d=120-100=20

The difference between two consecutive terms is constant

Therefore, it forms an A.P

980=100+(n-1)(20)

980-100=20(n-1)

880=20(n-1)

\frac{880}{20}=n-1

44=n-1

n=44+1=45

Total three digits number=900

The three digits numbers which are neither divisible by 4 nor 5=900-(225+180-45)=540

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