Question

how many three digit odd numbers can be formed using the digits 1,2,3,4,5,6, when the repetition of digits is not allowed?

Answer 1

i can be 2,5,1 because when the repetition digits is no allowed the can be 125 hope it help u bye

Answer 2

AnswEr:

For a number to be odd, must have 1,3 or 5 at the unit's place. So, there are 3 ways of filling the unit's place.

• Since the repetition of the digit is not allowed, the ten's place can be filled with any of the remaining 5 digits in 5 ways.

Now, four digits are left. So, hundred's place can be filled in 4 ways.

$\qquad\mathfrak{So,required\;number\:of\:numbers:-}$

= 3 × 5 × 4 = 60.

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If we talk about repetition of digit is allowed :

• Since the repetition of digit is allowed, so each of the ten's and hundred's place can be filled in 6 ways.

Hence, the required number of numbers :

= 3 × 6 × 6 = 108.