How many three digits are divisible by 8
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Answer:
Step-by-step explanation:
First divisable 3 digit is 104
Last divisable 3 digit 992
i.e. 104+8x=992
x = 111
i.e. 111 values without first divisable 3 digit number (104).
Include the first one
111 + 1 = 112
Totally 112.
Simply 104+(8x-1)=992
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