Question

how many tiles are required to cover a floor 4m x 3.2 m if each Tile measure 16cm X 16cm​

Answer 1

Answer:

Answer:

600 tiles are required

Step-by-step explanation:

Length of floor = 6 m = 600 cm

Breadth of floor = 4 m = 400 cm

Area of floor =  

Area of floor =  

Area of floor =  

Area requires by 1 tile = 400 sq.cm.

No. of tiles required for the floor =  

                                                   =

Answer 2

⇒ Given:

Length of the floor = 4 m

Breadth of the floor = 3.2 m

Length of the tile = 16 cm

Breadth of the tile = 16 cm

⇒ To Find:

The no. of tiles required to cover the floor.

⇒ Formulae to be used:

→ $\sf{Area\:of\:a\:rectangle=lb}$

→ $\sf{Area\:of\:a\:square=a^2}$

→ $\sf{\dfrac{Area\:of\:floor}{Area\:of\:1\:tile}}$

→ $\sf{1\:m^2=10000\:cm^2}$

⇒ Steps to solve:

→ Find area of floor.

→ Find the area of tile.

→ Convert the area from m² to cm².

→ Divide the area of one tile from the area of the floor.

⇒ Solution:

Length of the floor = 4m

Breadth of the floor = 3.2 m

Area of the floor = lb

= 4 x 3.2

= 12.8 m²

Length of the tile = 16 cm

Breadth of the tile = 16 cm

Area of the tile = a²

= 16 x 16

= 256 cm²

To convert m² to cm², multiply with 10000 cm².

To covert 12.8 m² to cm²:

= 12.8 x 10000

= 128000 cm²

No. of tiles required:

$\sf{=\dfrac{Area\:of\:floor}{Area\:of\:1\:tile}}$

$\sf{=\dfrac{128000}{256}}$

$\sf{=500\:tiles}$

Hence the required no. of tiles is 500.