how many tiles each 25 CM by 20 CM are required for the floor of a room 12 metre long and 9 metre wide
Answers
Answer:
216 bricks
Step-by-step explanation:
= 1200×900/20×25
= 1080000/500
two zeroes are cancelled on both numerator and denominator ,we get
= 10800/5
= 216 bricks
The number of tiles required = 2160
Explanation:
Given : Length of tile = 25 cm
Breadth of tile = 20 cm
We assume that the tiles are in rectangular shape.
Area of tile = Length x Breadth
= 25 x 20 = 500 sq. cm
The length of the floor= 12 metres = 12 x 100 = 1200 cm [∵ 1 m = 100 cm]
The breadth of the room = 9 metres = 900 cm
Area of the floor = Length x Breadth
= 1200 x 900 = 1080000 sq. cm
Now , the number of tiles required = (Area of the floor ) ÷ (Area of each tile )
= 1080000 ÷ 500 =2160
Hence , the number of tiles required = 2160
# Learn more :
The floor of the room is covered with 20 tiles of area 30 Sq.cm each.What is the area of the floor?
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