Math, asked by payalkhushi21, 9 months ago

how many tiles each 25 CM by 20 CM are required for the floor of a room 12 metre long and 9 metre wide​

Answers

Answered by manoj9325
7

Answer:

216 bricks

Step-by-step explanation:

= 1200×900/20×25

= 1080000/500

two zeroes are cancelled on both numerator and denominator ,we get

= 10800/5

= 216 bricks

Answered by JeanaShupp
7

The number of tiles required = 2160

Explanation:

Given : Length of tile = 25 cm

Breadth of tile = 20 cm

We assume that the tiles are in rectangular shape.

Area of tile =  Length x Breadth

= 25 x 20 = 500 sq. cm

The length of the floor=  12 metres =  12 x 100 = 1200 cm [∵ 1 m = 100 cm]

The breadth of the room = 9 metres = 900 cm

Area of the floor =   Length x Breadth

= 1200 x 900 = 1080000 sq. cm

Now , the number of tiles required = (Area of the floor ) ÷ (Area of each tile )

=  1080000 ÷ 500 =2160

Hence , the number of tiles required = 2160

# Learn more :

The floor of the room is covered with 20 tiles of area 30 Sq.cm each.What is the area of the floor?

https://brainly.in/question/2879949

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