how many tiles of 80 CM by 50 CM will be required for tiling a floor of 10 m by 8 m ?
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step1- length of tile= 80cm
breadth of tile=50cm
area= l*b
= 80*50
=4000sqcm
step2- length of floor= 10m
breadth of floor=8m
area=l*b
=10*8
=80sqcm
step3- no. of tiles required=4000/8
=500
ans= required tiles=500
*=multiply
/=divide
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