Question

how many tiles of 80 CM by 50 CM will be required for tiling a floor of 10 m by 8 m ?​

Answer 1

step1- length of tile= 80cm

breadth of tile=50cm

area= l*b

= 80*50

=4000sqcm

step2- length of floor= 10m

breadth of floor=8m

area=l*b

=10*8

=80sqcm

step3- no. of tiles required=4000/8

=500

ans= required tiles=500

*=multiply

/=divide