How many tiles of dimension 10 square inch are required to cover a floor of dimension of 5 feet by 4 feet ?
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Answer:
length of floor=5ft=5×12=60 inch
breath of floor=4ft=4×12=48 inch
area of floor= 60×48=2880 square inch
area of 1 tile=10 square inch
no. of tiles required=2880/10=288
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