How many tiles of dimensions 24cm×15cm will be required to cover a floor 18m long and 12m wide
Answers
Answered by
11
area of rectangle = l*b
18*12
216
tiles dimensions = 24*15
360
total tiles needed
360-216=
144 tiles.
18*12
216
tiles dimensions = 24*15
360
total tiles needed
360-216=
144 tiles.
Answered by
32
First find the area of tile and that of the floor also
area of tile=24×15
=360 cm²
area of floor=1800×1200 cm²
no. of tiles required=area of floor/area of tiles
=1200×1800/360
=1200×5
=6000
6000 tiles are required to cover the floor
area of tile=24×15
=360 cm²
area of floor=1800×1200 cm²
no. of tiles required=area of floor/area of tiles
=1200×1800/360
=1200×5
=6000
6000 tiles are required to cover the floor
Sarth45:
thanks for selecting my answer as brainliest
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