How many tiles whose length and breadth are 10 cm and 6 cm respectively are needed to fit in a rectangular region whose length and breadth are respectively 80 cm and 60 cm.
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Answer :
- 80 tiles
Given :
- Rectangular tiles
- Length = 10cm
- Breadth = 6cm
- Rectangular region
- Length = 80cm
- Breadth = 60cm
To find :
- Tiles
Solution :
Firstly we have to find the rectangular tiles and region
(1) Rectangular tiles
- Length = 10cm
- Breadth = 6cm
As we know that,
- Area of tile = length × breadth
Where , l is length (10cm) and b is breadth (6cm)
》Area of tile = length × breadth
》10 × 6
》60cm²
(2) Rectangular region :
- Length = 80cm
- Breadth = 60cm
As we know that,
- Area of region = length × breadth
where , l is length (80cm) and b is breadth (60cm)
》Area of region = length × breadth
》80 × 60
》4800 cm²
Now we have to find the tiles :
- Number of tiles = Area of rectangular tile/Area of rectangular region
》4800/60
》80
Hence , 80 tiles
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