Math, asked by harshkarchuli123, 10 months ago

How many tiles whose length and breadth are 13 cm and 7 cm respectively are needed to cover a rectangular reason whose length and breadth are 520 cm and 140 CM

Answers

Answered by spsnehasourabh6
3

Answer:

800 tiles

Step-by-step explanation:

Area of 1 tile

13×7

91cm {}^{2}

Area of the floor

=

520 \times 140 \\ 72800cm {}^{2}

Area of floor / Area of 1tile= No.of tiles

Please mark it the brainliest........ It's a request

Answered by Anonymous
3

\huge\bold\green{Explanation}

According to the question we have :-

→ Length of tile = 13cm

→ Breadth of tile = 7 cm

→ Rectangular Region = 520 × 140

Simply , by using formula of area of rec. we can find it ,

\tt\green{Area\:of\: rectangle=length\times breadth}

Now, according to the question by substituting the known values in formula we get :-

→ Length of tile = 13cm

→ Breadth of tile = 7 cm

\begin{lgathered}\tt = Area\:of\:tiles=13\times 7\\ \\ \tt\green = Area=91cm\end{lgathered}

Hence , the Area of region is :-

\begin{lgathered}\tt = Area\:of\:plot=530\times 140\\ \\ \tt\green= Area\:of\:plot=72800cm{}^{2}\end{lgathered}

\sf\orange{\:\: Required\:Tiles=\dfrac{Area\:of\:plot}{Area\:of\:tiles}}

\begin{lgathered}\tt = No.\:of\: tiles=\cancel{\dfrac{72800}{91}}\\ \\ \tt\green = No. \:of \: Tiles\: =800\end{lgathered}

Hence , the required tiles is 800

Similar questions