Math, asked by deepbrar8879, 10 months ago

How many tiles whose length and breadth are 13 cm and 7 cm respectively and needed to cover a rectangular vision whose length and breadth are 5 20 cm and 14 0 CM

Answers

Answered by dreamyy
1

No. of tiles = Area of larger rectangle (vision) / Area of one tile

area of rectangle = l x b

= 520 * 140 / 13 * 7

= 40 * 20

= 800 tiles

Answered by Anonymous
5

\huge\bold\green{Answer}

According to the question we have :- .

→ Length of tile = 13cm

→ Breadth of tile = 7 cm

→ Rectangular Region = 520 × 140

Simply , by using formula of area of rec. we can find it ,

\tt\green{Area\:of\: rectangle=length\times breadth}

Now, according to the question by substituting the known values in formula we get :-

→ Length of tile = 13cm

→ Breadth of tile = 7 cm

\begin{lgathered}\tt = Area\:of\:tiles=13\times 7\\ \\ \tt\green = Area=91cm\end{lgathered}

Hence , the Area of region is :-

\begin{lgathered}\tt = Area\:of\:plot=530\times 140\\ \\ \tt\green= Area\:of\:plot=72800cm{}^{2}\end{lgathered}

\sf\orange{\:\: Required\:Tiles=\dfrac{Area\:of\:plot}{Area\:of\:tiles}}

\begin{lgathered}\tt = No.\:of\: tiles=\cancel{\dfrac{72800}{91}}\\ \\ \tt\green = No. \:of \: Tiles\: =800\end{lgathered}

Hence , the required tiles is 800

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