Question

how many tiles with dimensions 12 cm and 5 cm will be needed to fit a region whose length and breadth are 144 cm and cm respectively​

Answer 1

Answer: hey mate here is ur answer mark it as brainliest

Step-by-step explanation:

Area of 1 tile = 12*5 = 60cm^

Area of the rectangular region = 144*100 = 14400cm^

No: of tiles required = area of the rectangular region / area of 1 tile

= 14400/60

= 240 tiles

Answer 2

Answer:

${\huge{\underline{\underline{\sf{\red{Question :-}}}}}}$

How many tiles with dimensions 12 cm and 5 cm will be needed to fit a region whose length and breadth are 144 cm and 100 cm respectively.

${\huge{\underline{\underline{\sf{\red{Solution :-}}}}}}$

Hence,

Length of the region (l) = 144 cm

Breadth of the region (b) = 100 cm

Therefore ,

Area of the region = l × b

= 144 × 100 sq cm = 14400 sq cm

Length of one tile = 12 cm

Breadth of one tile = 5 cm

Therefore,

Area of one tile = 12 × 5 sq cm

= 60 sq cm

Therefore,

Number of tiles required

$\frac{Area \: of \: the \: region }{Area \: of \: one \: tile } = \frac{14400}{60} = 240 \: tiles$