Math, asked by BaibhabBiswas, 9 months ago

How many times can the least number consisting of the digits 1, 2, 7, 9
from the greatest number consisting of the same digits and what will be the last
remainder?

Answers

Answered by mhanifa
6

Answer:

7 times and 768 reminder

Step-by-step explanation:

The least number consisting of the digits 1, 2, 7, 9= 1279

The greatest number consisting of the digits 1, 2, 7, 9= 9721

9721=7*1279+768

So bigger number is 7 time more than the smaller one and the reminder is 768

Answered by amandeepkaurgill5885
1
7times and 768 remainder
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