Science, asked by ahadpadania7871, 1 year ago

How many times concentrated will be the aqueous solution having pH 11.9 as compared to aqueous solution having pH 8 ?

Page 152 Chapter - 7.Acids, Bases and Salts

Answers

Answered by sonuvuce
0

Answer:

The aqueous solution having pH 8 is 7937 times more concentrated than the aqueous solution having pH 11.9

Explanation:

pH of the first  aqueous solution = 11.9

We know that if [H^+] is the concentration of the H^+ ions then the pH is given by

\boxed{pH=-\log_{10}[H^+]}

\implies \boxed{[H^+]=10^{-pH}}

Therefore the concentration of H^+ ions in the aqueous solution of pH 11.9 is

[H^+]_{1}=10^{-11.9}=10^{-11}\times10^{-0.9}=1.26\times 10^{-12}

The concentration of H^+ ions in the aqueous solution of pH 11.9 is

[H^+]_{2}=10^{-8}

Therefore

\frac{[H^+]_2}{[H^+]_1} =\frac{10^{-8}}{1.26\times 10^{-12}} =\frac{10000}{1.26} = 7936.5 ≈ 7937

Therefore, the aqueous solution having pH 8 is 7937 times more concentrated than the aqueous solution having pH 11.9

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