Question

how many times does the digit 2 occur in tens place in the numbers from 200 to 2000?​

Answer 1

Answer:

180

Step-by-step explanation:

220----229,320----329,420---429.......

if we calculate we find that

18*10

=180

180 times

Answer 2

Answer:

For 180 times the digit 2 occurs in tens place in numbers from 200 to 2000.

Step-by-step explanation:

• 2 occur in tens place that means the place value of 2 will be = 2 × 10

                                                                                                              = 20

• For the numbers from 200 to 300, 2 comes in tens place for the following numbers : 220, 221, 222, 223, 224, 225, 226, 227, 228, 229.

      We can say in (300 - 200=) 100 numbers , 2 comes in tens place for 10 times.

• Between 200 and 2000 there are total (2000 - 200) = 1800 numbers.

       Among 100 there are only 10 numbers present with 2 in tens place.

      Among 1800 there are 10 × $\frac{1800}{100}$ = 180 numbers present with 2 in tens place.

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