How many times does the digit 3 appear while writing the integers from 1to 1000?
Answers
Answer:
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Answer:
So there are 3 * 9 = 27 such numbers. In each of these 27 numbers, the digit 3 is written twice. Therefore, 3 is written 54 times.
Step-by-step explanation:
This is P&C question
Any number between 1 and 999 can be expressed in the form of xyz where 0 < x, y, z < 9.
Case 1. The numbers in which 3 occurs only once. This means that 3 is one of the digits and the remaining two digits will be any of the other 9 digits
You have 1*9*9 = 81 such numbers. However, 3 could appear as the first or the second or the third digit. Therefore, there will be 3*81 = 243 numbers (1-digit, 2-digits and 3- digits) in which 3 will appear only once.
Case 2. The numbers in which 3 will appear twice. In these numbers, one of the digits is not 3 and it can be any of the 9 digits.
There will be 9 such numbers. However, this digit which is not 3 can appear in the first or second or the third place. So there are 3 * 9 = 27 such numbers.
In each of these 27 numbers, the digit 3 is written twice. Therefore, 3 is written 54 times.
Case 3. The number in which 3 appears thrice - 333 - 1 number. 3 is written thrice in it.
Therefore, the total number of times the digit 3 is written between 1 and 999 is 243 + 54 + 3 = 300