Question

if ( 2x^2-5y^2):xy=1:3 find y:x​

Answer 1

We can find in the given ratio.

$( 2x^2-5y^2):xy=1:3$

∴$3(2x^2-5y^2)=xy$

Since it is an equation, we can solve for a variable.

$6x^2-xy-15y^2=0$

$(3x-5y)(2x+3y)=0$

∴$3x-5y=0$ or $2x+3y=0$

We can solve for y.

$5y=3x$ ∴$y=\frac{3}{5} x$

$3y=-2x$ ∴$y=-\frac{2}{3} x$ (x) Ratio should not contain negative value.

∴$\frac{3}{5} x:x=3:5$

Therefore, y:x=3:5

Answer 2

Answer:

5:3

Step-by-step explanation:

On solving u get 5y=3x

x/y=5/3

x:y=5:3