Math, asked by dhruvkohli1611, 9 months ago

if ( 2x^2-5y^2):xy=1:3 find y:x​

Answers

Answered by TakenName
2

We can find in the given ratio.

( 2x^2-5y^2):xy=1:3

3(2x^2-5y^2)=xy

Since it is an equation, we can solve for a variable.

6x^2-xy-15y^2=0

(3x-5y)(2x+3y)=0

3x-5y=0 or 2x+3y=0

We can solve for y.

5y=3xy=\frac{3}{5} x

3y=-2xy=-\frac{2}{3} x (x) Ratio should not contain negative value.

\frac{3}{5} x:x=3:5

Therefore, y:x=3:5

Answered by epfolak12
0

Answer:

5:3

Step-by-step explanation:

On solving u get 5y=3x

x/y=5/3

x:y=5:3

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