How many times does the digit 5 occur in tens place in the Natural numbers up to 100? with methods
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1
50,51,52,53.........59
last term. = 59
=> 50 + ( n - 1 ) 1 = 59
=> n - 1. = 9
=> n = 10
the digit 5 occur in tens place 10 times
Answered by
0
50,51,52,53,........59.
= 50 + (n-1) 1 = 59
= n-1. =9
= n. =10.
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