Math, asked by neetukhushdps, 5 months ago

how many triangles can a nonagon divided if the diagonals are drawn from only 1 vertex

Answers

Answered by ⲎσⲣⲉⲚⲉⲭⳙⲊ

Answer:

Nonagon contains 9 sides and 9 vertices

As a triangle can be formed from any of the 3 points of the vertices of the nonagon…..so the required no of ways are ^9 C↓3…ie 9/3*8/2*7/1 which equals 84

Answered by ⲎσⲣⲉⲚⲉⲭⳙⲊ

Answer:

Nonagon contains 9 sides and 9 vertices

As a triangle can be formed from any of the 3 points of the vertices of the nonagon…..so the required no of ways are ^9 C↓3…ie 9/3*8/2*7/1 which equals 84

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