Question

How many two digit no. divisible by 3​

Answer 1

Hello ❣️

Answer

Lowest two digit no. Divisible by 3 is 12

And highest is 99

AP_____

12, 15, 18,........99

tn=99

a=12

d=15-12=3

n=?

$tn = a + (n - 1)d \\ 99 = 12 + (n - 1)3 \\ 3n - 3 = 87 \\ n - 1 = 29 \\ n = 30$

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Answer 2

Here Is Your Ans ⤵

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Given :-

Highest two digit number divisible by 3 is 99 So the series starts with 12 and ends with 99

a = 12

D = 3

An = 99

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To Find :-

N = ?

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Solution :-

➡An = a + ( N - 1 )D

➡99 = 12 + ( N - 1 )3

➡99 = 12 + 3N - 3

➡99 = 9 + 3N

➡3N = 99 - 9

➡N = 90 / 3

➡N = 30

Therefore , there are $\fbox{30}$two digit numbers divisible by 3.

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