Question

how many two digit numbers are divisible by 3 find the ap​

Answer 1

first two digit no. divisible by 3 = 12

last two digit no. divisible by 3 = 99

d= 3

an= a+(n-1)d

99 = 12 + (n-1)3

99-12 = 3n-3

87 = 3n-3

90 = 3n

n = 30

30 numbers are divisible by 3.

hope it helps you.

Answer 2

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