Question

How many values of x exist for which p(x)=x^2 - x +2 has/ have negative value ?

Answer 1

there is no any value of x which is negative and and =0

Answer 2

There are no values of x exist which are negative.

Step-by-step explanation:

Given, p(x) = x² - x + 2

Now, p(x) = 0

=> x² - x + 2 = 0

By using quadratic formula,

x = $\frac{-(-1) +/-\sqrt{ (1 -4(1)(2))}}{2}$

x = $\frac{1 +/-\sqrt{-7} }{2}$

x = $\frac{1+/-7i}{2}$

So, the values of x are imaginary.

Hence, there are no values of x exist which are negative.