Question

How many vibrations will a tuning fork of frequency 280hz complete during the time sound travels forward in air 20m. Take speed of sound in air as 340m/s.

Answer 1

Given:
Speed of sound=340m/s
Distance=20m
Speed =distance/time
time=distance/speed
time=20/340
=0.05sec
Frequency=280Hz
Frequency= No.of Vibrations in one second=280Hz
Therefore number of Vibrations completed in 0.05sec
=280x0.05=14 Vibrations

Answer 2

Answer:

Explanation:Given:

Speed of sound=340m/s

Distance=20m

Speed =distance/time

time=distance/speed

time=20/340

=0.05sec

Frequency=280Hz

Frequency= No.of Vibrations in one second=280Hz

Therefore number of Vibrations completed in 0.05sec

=280x0.05=14 Vibrations