Question

how many volume of chlorine is required to form 11.2l of HCl at 273 Kelvin and 1 atom of pressure​

Answer 1

Answer:

0.0111 L volume of chlorine is required to form 11.2L of hcl at 273K and 1atm pressure.

Explanation:

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Answer 2

Answer:

0.0111 L volume of chlorine is required to form 11.2L of hcl at 273K and 1atm pressure.

Explanation:

Formation of HCl will take place as follows.

            H2+cl2⇒2HCL

The data is given as follows.

           V = 11.2 L,    T = 273 K,   and P = 1 atm

Hence, calculate the number of moles as follows.

                         PV = nRT

    1 atm×11.2 L=n×0.0821 atm L /mol K×273 K

                     n = 0.499 mol

Therefore, according to the reaction equation 2 moles of HCl is formed by 1 mole of chlorine. Hence, volume of chlorine formed by 0.499 mol will be as follows.

                            0.499 mol /2

                          = 0.2495 mol

                          =  0.2495 mol  ×22.4 L / mol

                          = 0.0111 L

Therefore, volume of chlorine will be 0.0111 liter.