Question

how many water molecules are produced in the complete neutralization of one mole of phosphoric acid and potassium hydroxide

Answer 1

Answer:- $1.81*10^2^4H_2Omolecules$

Solution:- The balanced equation between potassium hydroxide and phosphoric acid is:

$3KOH+H_3PO_4\rightarrow \rightarrow K_3PO_4+3H_2O$

from this equation, there is 1:3 mol ratio between phosphoric acid and water.

So, if 1 mole of phosphoric acid is completely neutralized then we get 3 moles of water that could be converted to molecules on multiplying by Avogadro number. The set could be shown using dimensional analysis as:

$1molH_3PO_4(\frac{3molH_2O}{1molH_3PO_4})(\frac{6.022*10^2^3molecules}{1mol})$

= $1.81*10^2^4H_2Omolecules$

So, $1.81*10^2^4$ water molecules are produced by the complete neutralization of one mole of phosphoric acid and potassium hydroxide.

Answer 2

Answer: 3 molecules of water

Explanation:

Potassium hydroxide and phosphoric acid react to form potassium phosphate and water according to the equation.

3KOH(aq)+H3PO4(aq)---->K3PO4(aq)+3H2O(l)