Question

how many ways a batsman can score 200 with only 4's and 6's

Answer 1

it not going to happen

Answer 2

Answer:

The batsman can score 200 in 16 ways

Step-by-step explanation:

Step 1:

Taking the no. of fours and sixes to be x and y respectively,

Step 2:

We can say,

4a+6b=200  (Divide by 2)

a= (100-3b)/2

Now, a must belong to whole number, thus we can say 3b<100, (3b≠100)

Step 3:

Thus maximum value of b should be 33.

Now, regarding the equation, (100-3b) should be even, and thus y should also be even.

Step 4:

Thus, maximum value of   b is 32.

Now, by AP,

32=0+(n-1)2 ⇒n=17 (no. of even terms from 32 to 0 is 17)

Step 5:

Thus, in 17 ways, the situation is possible

If considered number of sixes never to be 0 number of ways=16