How many ways are there to distribute hands of 5 cards to each of four players from the standard deck of 52 cards? How many of these is such that each one get an ace?
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Answered by
6
52! 27! 5! 5!
The answer is 52!(5!×5!×5!×5!×32!)=1.4782628e+24
The answer is 52!(5!×5!×5!×5!×32!)=1.4782628e+24
Answered by
13
Answer:
Step-by-step explanation:
- we have to give 5 cards each to four players
- for first player 52c5
- for second player 47c5
- for third player 42c5
- for fourth player 37c5
- ans=52C5x47C5x42C5x37C5
- for each one to get an ace
- 1st player 48C4x4C1
- 2nd player 44C4x3C1
- 3rd player 40C4x2C1
- 4th player 36C4x1C1
- ans=48C4x4C1x44C4x3C1x40C4x2C1x36C4x1C1
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