Question

How many ways are there to place 12 indistinguishable (identical) balls into 8 bins with different colors?

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given :- How many ways are there to place 12 indistinguishable (identical) balls into 8 bins with different colors ?

Answer :-

→ Total identical balls = 12

→ Total bins = 8

we know that, n identical balls can be place in m different beans in :-

• (n + m - 1)! / (n!) * (m - 1)! ways .

so, putting n = 12 and m = 8, we get,

→ Total number of ways = (12 + 8 - 1)! / (12!) * (8 - 1)! = 19! / 12! * 7! = (19 * 18 * 17 * 16 * 15 * 14 * 13 * 12!) / 12! * (7 * 6 * 5 * 4 * 3 * 2 * 1) = (19 * 18 * 17 * 16 * 15 * 14 * 13) / (7 * 6 * 5 * 4 * 3 * 2) = (19 * 3 * 17 * 4 * 3 * 2 * 13) / 3 * 2 = 19 * 3 * 17 * 4 * 13 = 50388 ways (Ans.)

Learn more :-

let a and b positive integers such that 90 less than a+b less than 99 and 0.9 less than a/b less than 0.91. Find ab/46

p...

https://brainly.in/question/40043888