How many ways students can sit in a row of n seats each student has an emty seat immediately to his left
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The number of combinations of n objects taken 2 at a time is
N = n! / [(2!) * (n - 2)!]
Since the above value for N does not specify the order of a student and an empty seat the number of possible ways to have the empty seat on the left is N / 2 where N is given above.
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