Question

How many whole numbers are there between 244 and 332 which are exactly divisible by 7?

Answer 1

Answer:

43/6 = 7, remainder = 1. Hence 5 more should be added to 43 to get the minimum

number divisible by 6 between 43 and 200.

=> Minimum number divisible by 6 between 43 and 200 = 43 + 5 = 48

200/6 = 33, remainder = 2. Hence 2 should be decreased from 200 to get the maximum

number divisible by 6 between 43 and 200.

=> Maximum number divisible by 6 between 43 and 200 = 200 - 2 = 198

Hence, natural numbers numbers divisible by 6 between 43 and 200 are 48, 54, 60,...198

This is Arithmetic Progression with a = 48, d = 6, l=198

Number of terms l-a÷d+1=198-45÷6+1=150÷6-1=25+1=26