Question

How many words does the letter cordial form without repetition such that vowels occupy the even place?

Answer 1

Answer:

144

Explanation:

3!*4!=144

Answer 2

Answer:

144 words, the letter “CORDIAL” forms without repetition, with vowels occupying even place.  

Steps for calculation:

Number of letters in ‘CORDIAL’ = 7  

Number of Vowels = 3; Number of Consonants = 4;

Number of even places = 3

In the word ‘CORDIAL’, 3 vowels are to be placed in 3 places.

Thus, the number of ways to be =   1

Arrangement of vowels will be = 3! $=3 \times 2 \times 1=6$

Arrangement of consonants will be = 4! $=4 \times 3 \times 2 \times 1=24$

Thus, Total number of words $=1 \times 24 \times 6=144$