Question

How March area of metal sheet is required to make an open cylindrical tank of radius 2.8 m and height 120 m ?

Answer 1

curved surface area of cylinder = 2πrh
= 2•π•2.8•120
= 2111.15 m^2

area of base of cylinderical tank = π•r^2
= π•(2.8)^2 = 24.63 m^2

hence total area of sheet metal required = CSA + base area = 2111.15+24.63 = 2135.78 m^2