How may cubes of10cm edge can be put in a cubical box of 1 m edge?
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1 m = 100 cm
no of cubes = 100 into 100 into 100 / 10 into 10 into 10
no of cubes = 1000
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10cm=0.1m
Edge of the box 1m
V of the cubical box=1*1*1=1m^3
V of the cube=0.1*0.1*0.1=0.001m^3
therfore:- No of cubes=v of the cubical box / V of the cube
=1/0.001
No of cubes= 1000
Edge of the box 1m
V of the cubical box=1*1*1=1m^3
V of the cube=0.1*0.1*0.1=0.001m^3
therfore:- No of cubes=v of the cubical box / V of the cube
=1/0.001
No of cubes= 1000
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