Question

how may three digit nos r divisible by 9​

Answer 1

Step-by-step explanation:

solution.............

Answer 2

Answer:

100 three digit numbers are divisible by 9.

Step-by-step explanation:

108, 117, 126,..........., 999

This forms an A.P

$here \: \: a = 108 \\ d = 9 \\ an = 999 \\ \\ \ - - > an = a + (n - 1) \times d \\ 999 = 108 + (n - 1) \times 9 \\ 999 = 108 + 9n - 9 \\ 999 = 99 + 9n \\ 9n = 999 - 99 \\ 9n = 900 \\ n = \frac{900}{9} \\ n = 100$

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