Question

how may water molecules are present in 10 g of ice ​

Answer 1

Answer:

In 1 mole of anything there are 6.022 × 10²³ molecules (Avogadro's constant), so in 10 g of water there are (0.556 mol)(6.022 × 10²³ molecules/mol) = 3.35 × 10²³ molecules. (Note that it does not matter whether you have ice, liquid water, or steam)

Explanation:

Answer 2

1 g of water contains (6.022 x 10^23)/ 18 water molecules and the number comes out to be 3.3455 x 10^22. So the number of water molecules present in 1 g of water is 3.3455 x 10^22.

In 1 mole of anything there are 6.022 × 10²³ molecules (Avogadro's constant), so in 10 g of water there are (0.556 mol)(6.022 × 10²³ molecules/mol) = 3.35 × 10²³ molecules.

HOPE IT HELPS

MARK AS BRAINLIST DEAR ✌️

#ALWAYS be like wild child ❤️