Question

How much above the surface of earth does the acceleration due to gravity reduces by 36% of its value on the suraface of earth. Radius of earth = 6400 km.

Answer 1

Since, the acceleration due to gravity reduces by 36%, then the value of acceleration due to gravity 


there is = 100 - 36 = 64%. It means, g' = 64/100 g. If h is the height of location above the suraface of earth,


then g' = g R2/(R + h)2 or 64/100g = g R2/(R + h)2       or       8/10 = R/R + h


or  8 R + 8 h = 10 R


or  h = 2 R/8 = R/4 = 6.4 x 106/4 = 1.6 x 106m....!!

hope this will help u

Answer 2

Answer:

Here is the answer.........