How much ammonia will be formed from 2.95 g of acetamide at STP CH,CONH, + NaOH → CH,COONa+NH3
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STP, temp is 0 celsius and pressure is 1 atm.
we have to convert the temp to kelvins (that is 0 + 273= 273 K) and 25.0 grams to moles that is
25.0 g N2 x ( 1 mole of N2 / 28.02 g N2) = .892 moles.
then we use the ideal gas law that is PV=nRT to determine the volume. we know P is 1 atm, V is unknown, n is .892 moles, R is a constant (known fact ) which is 0.0821 (liter-atm/k-mole) <------units for R, and we know the T is 273 k. plug in the values
(1atm) V = (.892 moles)(0.0821 L-atm/k-mole)(273 K) <------solve for V and you should get 20.0 liters.
make sure that all the units cancel out except for liters.
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