Question

The age of father is 2 years more than five times the age of his son.if the sum of their ages is 38 years, find the age of each of them

Answer 1

Step-by-step explanation:

let the age of father is x and age of son is y.

x + y = 38;

x = 5y + 2;

Now solving both the equations and finding the value of x and y.

Putting x = 5y+2 in x + y = 38;

we get;

5y+2+y = 38;

6y = 36;

y = 6 year is the age of son;

age of father is x = 5*6+2 = 32 year

Answer 2

Answer:

Here's the answer hope you find it helpful and mark me as brainliest pleasee ! Here is the step - by - step explaination!

let the age of father is x and age of son is y.

x + y = 38;

x = 5y + 2;

Now solving both the equations and finding the value of x and y.

Putting x = 5y+2 in x + y = 38;

we get;

5y+2+y = 38;

6y = 36;

y = 6 year is the age of son;

age of father is x = 5*6+2 = 32 year